ya...the answer to this math problem is: 5,940
Wiki User
∙ 2009-03-08 17:36:126x2=-7
It is: 6x2
solve -3x-3y=-15
6x2+13x-5 = (2x+5)(3x-1) when factored
6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y)
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
x3 6x2-x-30
33X Around the Sun - 2005 is rated/received certificates of: UK:15
6x2=-7
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
-3(2x + 1)(4 + 3x) = -3[8x + 6x2 + 4 + 3x] = -3[6x2 + 11x + 4] = -18x2 - 33x - 12.
33x + 9 = 18 ----> 33x = 9 ----> x = 3/11
They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.They are 6x1, 6x2, 6x3 and so on until 6x15.
80
(6 × 2) + 3 = 15
(12)(33x)(92-12x) (12)(33x)(92)-(12)(33x)(12x) 36432x-4752x2 if this restatement of the grouping in the original problem is correct.
(2x + 3)(3x - 5)