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ya...the answer to this math problem is: 5,940

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Q: Can you solve 6x2 33x 15?
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How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?

3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11


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What is the solution set for 6x2-x-15 equals 0?

6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3