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What is the sum of the prime numbers between 40 and 60?
The prime numbers between 40 and 60 are 41, 43, 47, 53 and 59. These sum to 243.
What is 8938 divisible by?
1, 2, 41, 82, 109, 218, 4469, 8938
What are the multiples of 41 up to 1000?
41, 82, ... Just keep adding 41 at a time.41, 82, ... Just keep adding 41 at a time.41, 82, ... Just keep adding 41 at a time.41, 82, ... Just keep adding 41 at a time.
What are all the multiples of 42 up to 100?
The first ten positive integer multiples of 41 are: 1 x 41 = 41 2 x 41 = 82 3 x 41 = 123 4 x 41 = 164 5 x 41 = 205 6 x 41 = 246 7 x 41 = 287 8 x 41 = 328 9 x 41 = 369 10 x 41 = 410
What are the values of abc and d if a is a is factor of b c is the second multiple of b and the fourth multiple of a d is a prime number between 10 and 20 and all numbers are different and add to 41?
1. a is a factor of b. 2. c = 2b = 4a, thus b = 2a and c = 4a. 3. d is prime between 10 & 20. 4. a + b + c + d = 41. Therefore: a + 2a + 4a + d = 41 7a + d = 41 d = 41 - 7a The only integer value for awhich results in d being a prime between 10 and 20 is where a = 4. If a = 4 then b = 2a = 4 * 2 = 8 c = 4a = 4 * 4 = 16 d = 41 - (7*4) = 41 - 28 = 13 The numbers are thus 4,8,16 and 13.
