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1. a is a factor of b.

2. c = 2b = 4a, thus b = 2a and c = 4a.

3. d is prime between 10 & 20.

4. a + b + c + d = 41.

Therefore: a + 2a + 4a + d = 41

7a + d = 41

d = 41 - 7a

The only integer value for awhich results in d being a prime between 10 and 20 is where a = 4.

If a = 4 then

b = 2a = 4 * 2 = 8

c = 4a = 4 * 4 = 16

d = 41 - (7*4) = 41 - 28 = 13

The numbers are thus 4,8,16 and 13.

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Q: What are the values of abc and d if a is a is factor of b c is the second multiple of b and the fourth multiple of a d is a prime number between 10 and 20 and all numbers are different and add to 41?
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