1,080 is evenly divisible by these numbers: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 27, 30, 36, 40, 45, 54, 60, 72, 90, 108, 120, 135, 180, 216, 270, 360, 540 and 1,080.
The GCF is 10.
No, 590 is divisible by 2, 5 and 10.
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
If a number is divisible by 10 it cannot give any remainder other than 0. That is what "divisible by" means!
Yes.
A four-digit number that meets these criteria is 1080. It is an even number (divisible by 2), divisible by 9 (1080 ÷ 9 = 120), divisible by 10 (1080 ÷ 10 = 108), and divisible by 3 (1080 ÷ 3 = 360). However, it is also divisible by 3, so it does not satisfy your request for a number that is not divisible by 3. Instead, a correct example is 1086, which is even and divisible by 9 (1086 ÷ 9 = 120.67) but not by 3. Hence, no valid 4-digit number meets all criteria simultaneously.
1080/45 = 24
Two: 1020 and 1080.
I think you mean which of the numbers 2,3,5,6,9 or 10 are 1080 divisible by? All of the numbers can be divided into 1080 and get a whole integer
Any multiple of 90 from 1080 to 9990.
1080 is divisible by all of those numbers...1080 divided by 2 = 5401080 divided by 3 = 3601080 divided by 5 = 2161080 divided by 6 = 1801080 divided by 9 = 1201080 divided by 10 = 108
2 and 3
Yes, 60 times.
1080
The GCF is 10.
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 27, 30, 36, 40, 45, 54, 60, 72, 90, 108, 120, 135, 180, 216, 270, 360, 540, 1080.
1080 divided by 10 = 108