Yes.
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It is divisible by 2, 5 and 10 but not the rest.
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Any element of the union of the following two sets:{the set of numbers of the form 689*k, where k is an integer} and{the set of numbers of the form 10*k, where k is an integer}is evenly divisible by 689 or by 10.
No, 6 is not divisible by 148. In order for one number to be divisible by another, the first number must be a multiple of the second number. In this case, 6 is not a multiple of 148 as it is much smaller. Therefore, 6 is not divisible by 148.
It isn't. 438 is divisible by 6 because 438 is a multiple of 6.