It is divisible by 2, 5 and 10 but not the rest.
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Any element of the union of the following two sets:{the set of numbers of the form 689*k, where k is an integer} and{the set of numbers of the form 10*k, where k is an integer}is evenly divisible by 689 or by 10.
No, 6 is not divisible by 148. In order for one number to be divisible by another, the first number must be a multiple of the second number. In this case, 6 is not a multiple of 148 as it is much smaller. Therefore, 6 is not divisible by 148.
It isn't. 438 is divisible by 6 because 438 is a multiple of 6.
60
60
60 000 000.
60
60
60
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
60 divided by 6 = 10 60 divided by 15 = 4
60
Yes. 60/2 is 30. (If a number ends in 0, 2, 4, 6, or 8 it is divisible by two.)
To determine if 610 is divisible by both 6 and 10, we need to check if it is divisible by both 6 and 10 individually. For 6, we check if 610 is divisible by 2 and 3. Since 610 is even but not divisible by 3, it is not divisible by 6. For 10, we check if 610 ends in 0, which it does not. Therefore, 610 is not divisible by 10 either.