Yes.
Yes, it is.
It is divisible by 2, 5 and 10 but not the rest.
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Any element of the union of the following two sets:{the set of numbers of the form 689*k, where k is an integer} and{the set of numbers of the form 10*k, where k is an integer}is evenly divisible by 689 or by 10.
It isn't. 438 is divisible by 6 because 438 is a multiple of 6.
60
60
60
60 000 000.
60
60
60
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
The number 30 is the smallest whole number divisible by both 10 and 6.
Every number is divisible by any non-zero number. However, 610 cannot be evenly divided by both 6 and 10 and so is not divisible by 6 and 10.
60 divided by 6 = 10 60 divided by 15 = 4
60