No. 105 is divisible by these numbers: 1, 3, 5, 7, 15, 21, 35, 105.
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No, 590 is divisible by 2, 5 and 10.
Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
As a product of its prime factors: 3*5*5*19 = 1425 or as 3*52*19 = 1425
If a number is divisible by 10 it cannot give any remainder other than 0. That is what "divisible by" means!