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What is the divisibility rule for the number 27?
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
What is the divisibility rule for 27?
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
What is the remainder when 189ˏ540 is divided by 27?
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
What is the smallest number which must be added to 368 to make it exactly divisible by 27?
you must add 10 368+10=378 378/27=14 If you divide 368 by 27, you get 13 and remainder 17. So you add 10.
What is the divisibility rule for 3?
A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.
How do you know what number can be added to 368 to make it divisible by 27?
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
What is the LCM of 27 10 12 and 8?
Well, because it has to be a multiple of 10, you know that it has to end with a 10. The 27 is the biggest number and will be what we focus on. To get the 27 into a multiple of 10, we have to multiply it by 10.10 x 27 = 270.270 is not divisible by 12 or 8, so we continue.Keeping in mind that the number has to be a multiple of 10 and 27, we can only add intervals of 270.270+270 = 540.540 is divisible by 27, 10 and 12, but not by 8. So lets add another 270.540+270 = 810810 is only divisible by 10 and 27, much like 270, so lets add another 270.810+270 = 10801080 is divisible by 27, 10, 12 and 8 and is the lowest common multiple.
What is the divisibility rule for the number 27?
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
What number is 27 divisible by?
9
What is the divisibility rule for 27?
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
Is 270 divisible by 10?
Yes, it is 27
What number is divisible by 27 and 45?
1,215
What number is divisible by 27 and 36?
972 is one of the numbers that is divisible by both.
What is the remainder when 189ˏ540 is divided by 27?
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
What number is divisible by 5 with a remainder of 2 and divisible by 6 with a remainder of 3?
How about 27
What is the number 81 divisible by?
81 is divisible by 1, 3, 9, 27 and 81
What is the smallest number which must be added to 368 to make it exactly divisible by 27?
you must add 10 368+10=378 378/27=14 If you divide 368 by 27, you get 13 and remainder 17. So you add 10.
