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What is the divisibility rule for the number 27?
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
What is the divisibility rule for 27?
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
What is the remainder when 189ˏ540 is divided by 27?
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
What is the divisibility rule for 3?
A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.
What is the smallest number which must be added to 368 to make it exactly divisible by 27?
you must add 10 368+10=378 378/27=14 If you divide 368 by 27, you get 13 and remainder 17. So you add 10.
