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The least common multiple of the numbers 9, 5 and 10 is 90.
For any larger number for which you have to test divisibility, split this factor up into smaller numbers. For example, you know that 2340 is divisible by 90 because you can divide it by 10 (2340 / 10 = 234), and then you can divide 234 by 9 (234 / 9 = 26).
They are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
No, 590 is divisible by 2, 5 and 10.
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
90 is divisible by 10 since 90/10 = 9. It should be obvious that 90 is not divisible by 234,569 which is much larger than 90.
2, 4
No.
Yes: 90 ÷ 10 = 9
Well, isn't that a happy little question? Let's take a closer look. If a number is divisible by 5, it must end in 0 or 5. And if a number is divisible by 9, the sum of its digits must also be divisible by 9. When we add the digits of 90 (which is 9 + 0 = 9), we see that it is divisible by 9 but not by 5.
All numbers divisible by 90 are also divisible by 9 and 10
It is "True".
Yes, 2796 / 3 is 932.
Not evenly. 932 and 936 both are
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
90 is divisible by 10 because it has a 0 as its end digit. Any number with a zero as the end digit gives an integer result when dividing by 10.
2, 4, 5, 8, 10, 20, 40, 233, 466, 932, 1165, 1864, 2330, 4660.