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It probalary should be around 224 MPH.. or 386 km. _______________________________________________________ whoa, way too fast. It's an algebra problem. Three equations Vp x time = 400km Vf x time = 330km Vp=Vf+14 km/hr and three unknowns (the time, and speed of each type of train). I used substituion, targeting an equation with only time. Long story short it solved to 5 hours (which makes sense after I did all that work and figured out that the additional 70km would take a train that is 14km faster...five hours to cover). Knowing the freight train can go 330km in 5 hrs (eq #2), it's speed is 330/5 or 66km/hr.knowing passenger train can go 440km in five hours (eq 1), it's speed is 400/5 or 80km/hr. ...and those speeds are 14km/hr apart, so we know we're good.

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