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Q: Three consecutive multiples of 4 have a sum of 120. What is the greatest of these numbers?

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1422, 1431, 1440

504, 756, 1008

91

42 of them.

33 and 1/3%

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The answer to that question is 49,50,51

The numbers would be 8 + 10 + 12.

There are no sets of three consecutive numbers totaling 118.

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