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Q: What are the integers There are three consecutive multiples of nine The sum of the first two numbers is 2853?
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Related questions

What consecutive prime integers have a difference of 20?

The first two consecutive prime numbers that have a difference of 20 are the numbers 887 and 907.


Two consecutive negative integers have a product of 240 what are the integers?

First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.


What numbers is a consecutive composite numbers?

It's any set of consecutive integers that are composite. For instance, 8, 9, and 10 are consecutive composites.


What are the first ten consecutive composite numbers?

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123


The sum of two consecutive integers is -377 What are the integers?

Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188


What is the sum of the first four non-negative consecutive even integers?

The sum of the first four non-negative, consecutive, even integers is 20.


The sum of 3 consecutive even integers is 54 What is the first consecutive integer?

The first integer is 17.


Find 3 consecutive whole numbers such that the first and third add up to 118?

121


What is the sum of three consecutive integers if the sum of the first and third numbers is 33 less than 3 times the second number?

Their sum is 99.


What are 3 numbers that are in a row and have the sum of 9000?

First of all, you need to be more specific. It's three consecutive integers. And they are 2,999, 3,000, and 3,001


The sum of 4 consecutive integers is -82 what are the integers?

86


The sum of three consecutive even integers is 114?

Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.