It's not possible. For two numbers to have a sum of 13, one would have to be even, that is, divisible by 2.
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663 is divisible by: 1 3 13 17 39 51 221 and 663.
Any multiple of 45461.
a.
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
1, 2, 13, 26