663 is divisible by: 1 3 13 17 39 51 221 and 663.
Any multiple of 45461.
a.
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
1, 2, 13, 26
13 + 0
67, 76
Some positive numbers are divisible by 13, but not all of them.
The sum of the first 13 odd numbers is 169.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
Except for 2, all other prime numbers are odd. The sum of any two odd numbers is even. Therefore, the prime number 2 will evenly divide the sum of any other two prime numbers. Here are some examples to illustrate this: 3 + 5 = 8 which is evenly divisible by 2 13 + 19 = 32 which is evenly divisible by 2 43 + 47 = 90 which is evenly divisible by 2
The two numbers are 9 and 13.
There are 13 such numbers.
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
There's a trick you can use: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. Here 2+4+5+2 = 13. Is 13 divisible by 3? You decide.
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
They are: 312 and its multiples