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  1. Well i can't answer that because you'll be cheating.
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Q: What are the 3 numbers that can only provide 4 possible outcomes?
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Is rolling a single loaded die 58 times keeping track of the numbers tat are rolled binomial distrubition?

No. A binomial distribution consists of trials with only two possible outcomes. The experiment described in the question has six - unless the die is so seriously loaded that only two outcomes are possible.


If you shoot 5 free throws what are the possible outcomes?

The only possible outcomes are 1, 2, 3, 4, 5, or 0 points.


What in an event is the ratio of the number of favorable outcomes to the number of possible outcomes?

That's the 'probability' of a favorable outcome.but only if the outcomes are equally likely.


How many possible outcomes if each coin is flipped once?

We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).


Rolling a single die 34 times keeping track of the numbers rolled is this a bionomial distribution?

No. If you keep track of all the numbers that are rolled then there are six possible outcomes, a binomial has only two. It is a multinomial distribution.


What is the mode for numbers 27 4 9 2 10 0 18?

If the seven numbers are the only possible outcomes then there is no mode. Otherwise each one of the seven is a mode since they appear more often than the numbers that do not appear at all.


If you roll 2 4 faced dice how many outcomes are there?

The question is underspecified since the answer depends on the numbers on the dice. If all the numbers on both the dice are the same, there is clearly only one outcome. If the dice have 4 different numbers, then there can be 16 different outcomes. If the numbers on each die are 1,2,3 and 4 (or any four numbers in arithmetic sequence) there will be 7 outcomes.


How many 3 digit numbers can be formed from the digits 1 2 3 4 5 6 7 8 9 if each digit is used only once?

Multiply the number of possible starting numbers by the number of possible middle numbers by the number of possible end numbers to get your result.In example, The possible starting numbers are 1, 2, 3, 4, 5, 6, 7, 8, and 9. Let's say I picked nine as the starting number. Since your question states that each number can only be used once, we eliminate nine from the selection of middle and end numbers. Now, the choices for the possible middle and end numbers are 1, 2, 3, 4, 5, 6, 7, and 8.Possible starting numbers= 9Possible middle numbers= 8Multiply 9 by 8. You get 72 different choices for a two digit number.Let's say that the middle number I picked was two. We then remove the number two from the possible choices for the final numbeselections: 1, 3, 4, 5, 6, 7, and 8.Possible outcomes for two digit number= 72 (which is 9 times 8)Possible end numbers = 7Multiply 72 by 7 to get the possible outcomes for a three digit number with each digit used only once.72 times 7 = 504. You have 504 possible outcomes.


How is selecting one marble from each of 2 bags and tossing 2 coins similar?

It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.


How many possible outcomes if you roll a die 4 times?

It depends what you mean by outcome. If you are interested in the total number of different outcomes, then there are 6 x 6 x 6 x 6 or 1296 unique possible outcomes. If you are only interested in the total (the sum) of the resulting roll, it can be anything from 4 to 24 so there are just 21 possible outcomes.


How many outcomes are possible of a coin is tossed 3 times?

It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).


What is the mode of the data 6 4 3 2?

If any other number (1 or 5, for example) was a possible outcome, then the mode consists of all four numbers, 2, 3, 4 and 6 since these appear more often that the ones that did not appear at all. If the four numbers are the only possible outcomes, then there is no mode.