We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
7/8
all headsall tails3 heads 1 tail3 tails and 1 head2h and 2ti think only 5 but that's just what i can get===============================================The above answer is correct if you disregard the order of the outcomes.If the order of the outcomes matters, then the answer is:2 x 2 x 2 x 2 = 16since each toss has two possible outcomes (assuming the coin cannot land on its side) and you repeat the toss four times.
When flipping a coin, there are two possible outcomes: heads (H) or tails (T). If you flip one coin, there are 2 outcomes. If you flip multiple coins, the total number of outcomes is calculated as (2^n), where (n) is the number of coins flipped. For example, flipping 3 coins results in (2^3 = 8) possible outcomes.
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
When flipping a coin 8 times, each flip has 2 possible outcomes: heads or tails. Therefore, the total number of possible outcomes is calculated by raising the number of outcomes for one flip to the power of the number of flips: (2^8). This equals 256 possible outcomes.
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
When tossing a coin, there are two possible outcomes for each toss: heads (H) or tails (T). For three tosses, the total number of possible outcomes can be calculated using the formula (2^n), where (n) is the number of tosses. Thus, (2^3 = 8). Therefore, there are 8 possible outcomes when tossing a coin three times.
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.
I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8