y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)
x2-y2=(x-y)(x+y) which is a well known identity.
If that's y2, the answer is (y - 5)(y + 3)
9y-81=9*(y-9)
0.5(x - y)(2x + 2y - 3)
(y - 8)(y + 1)
(y + 5) (y + 2)
(x - y + 7)(x + y)
y2+7y=18 y2+7y-18=0 (y+9)(y-2)=0 y=-9 & y=2
(y - 5)(y - 6)
That factors to y(y2 + 7y - 5)
Simplify each expression
30
It is: y2
4x2-y2 = (2x-y)(2x+y)
You're looking for factors of 38 that have a difference of 17. Luckily, 38 only has two factor pairs. It's not 38 and 1. (y - 2)(y + 19)
factor 4y - 32