4x2-y2 = (2x-y)(2x+y)
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(3 - y + 2x)(3 + y - 2x)
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
dont know sorry
4x2-36x+81 (2x-9)(2x-9)
4x2 - 23xy + 15y2 = (4x - 3y)(x - 5y)