1,2,3,4,6,8,12,24
1,2,19,38
1,3,5,9,15,45
1,3,17,51
You've collected the combined set of all the proper factors of those four numbers. The full set of combined factors would include one and the numbers themselves. But that's not your question. There's a difference between "all factors" and "all thefactors." As stated, since those factors are not common to all four numbers, the answer is "no."
Everything you need is in here somewhere.
3: 1, 3
4: 1, 2, 4
5: 1, 5
6: 1, 2, 3, 6
7: 1, 7
8: 1, 2, 4, 8
9: 1, 3, 9
10: 1, 2, 5, 10
11: 1, 11
12: 1, 2, 3, 4, 6, 12
13: 1, 13
14: 1, 2, 7, 14
15: 1, 3, 5, 15
16: 1, 2, 4, 8, 16
17: 1, 17
18: 1, 2, 3, 6, 9, 18
19: 1, 19
20: 1, 2, 4, 5, 10, 20
21: 1, 3, 7, 21
22: 1, 2, 11, 22
23: 1, 23
24: 1, 2, 3, 4, 6, 8, 12, 24
25: 1, 5, 25
26: 1, 2, 13, 26
27: 1, 3, 9, 27
28: 1, 2, 4, 7, 14, 28
29: 1, 29
30: 1, 2, 3, 5, 6, 10, 15, 30
31: 1, 31
32: 1, 2, 4, 8, 16, 32
33: 1, 3, 11, 33
34: 1, 2, 17, 34
35: 1, 5, 7, 35
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
The common factors of 12 and 14 are 1 and 21 and 2
Factors of 12: 1, 2, 3, 4, 6 and 12. Factors of 14: 1, 2, 7 and 14.
The factors of 12 are: 1, 2, 3, 4, 6, 12 The factors of 14 are: 1, 2, 7, 14 The factors of 16 are: 1, 2, 4, 8, 16
The factors of 7 are: 1, 7The factors of 14 are: 1, 2, 7, 14
The greatest common factor of 5 and 14 is 1.
(4*10+11+2*12+13+2*14)/10 = 11.6
1 is a common factor of 11, 12, 13, 14 and 15.
By usual definitions of outliers, there is none.
11
7, 10, 11, 12, 13, 14, 17
The common factors of 12 and 14 are 1 and 21 and 2
10 7 11 12 9 13 14 11 15 16 13 17 18 15 19 20...
6, 10, 11, 12, 14, 14, 15, 22 mean: 13 median: 13 mode: 14 range: 16
14
Factors of 12: 1, 2, 3, 4, 6 and 12. Factors of 14: 1, 2, 7 and 14.
The factors of 12 are: 1, 2, 3, 4, 6, 12 The factors of 14 are: 1, 2, 7, 14 The factors of 16 are: 1, 2, 4, 8, 16
11