To find the common factors of 8 and 12, we first list the factors of each number. The factors of 8 are 1, 2, 4, and 8, while the factors of 12 are 1, 2, 3, 4, 6, and 12. The common factors are 1, 2, and 4. To find the sum of these common factors, we add them together: 1 + 2 + 4 = 7. So, the sum of all the common factors of 8 and 12 is 7.
8 and 5
The sum of the factors of any negative number is zero.
It is 496.496 = 24*31 so its proper factors are 2, 4, 8, 16, 31, 62, 124 and 248. Their sum is 495.
It is only possible to have one even prime factor of any number - as there is only one even prime number, 2. The sum of these is therefore 2.
The two consecutive numbers whose factors have the same sum are 8 and 9. The factors of 8 are 1, 2, 4, and 8, and their sum is 15. The factors of 9 are 1, 3, and 9, and their sum is also 15. Therefore, 8 and 9 are the consecutive numbers whose factors have the same sum.
Any of its factors including itself
It will have 34 sides
Factors for 16 are: 1, 2, 4, 8, 16 Sum = 1 + 2 + 4 + 8 + 16 = 31
The factors of 54 are 1, 2, 3, 6 9 18 27 54. The factors having a sum of 8 are 2 and 6.
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
8 and 12 are factors of 20, 8 + 12 = 20
They are: 14 and 4
Composite factors of 24 are 4, 6, 8, 12 and 24. Sum of composite factors = 4+6+8+12+24 = 54.
The two factors of 24 that give you a sum of 20 are 12 and 8.
The sum of the interior angles of a polygon with n sides is 180(n-2). Setting this equal to 5400 yields 180n - 360 = 5400 or 180 n = 5400 + 360 = 5760 or n = 5760/180 = 32 sides.
5 and 3.