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How many sides does a polygon have if the sum of the interior angles is 5400?
Wiki User
∙ 14y ago
The sum of the interior angles of a polygon with n sides is 180(n-2). Setting this equal to 5400 yields 180n - 360 = 5400 or 180 n = 5400 + 360 = 5760 or n = 5760/180 = 32 sides.
Wiki User
∙ 14y ago
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What is 5389 rounded to the nearest hundred?
5400
How many 60s are in 5400?
60 goes into 5400 exactly 90 times. This can be calculated by dividing 5400 by 60.
What is 810000000000 divided by 150000000?
5400
What is 150000000 times 5400?
5400 x 150000000 = 810000000000
What is 5447 rounded to the nearest 100?
5400
What is the sum of the interior angle of a polygon with 5400 degrees?
As in the question it is 5400 degrees. But a polygon whose interior angles add up to 5400 degrees will have 32 sides
What is the sum of the interior angles of a polygon with 32 sides?
They add up to 5400 degrees
What is the sum of the interior angle of a polygon with 32 sides?
The sum of interior angles of a polygon with 'n' sides = 180( n - 2 ) degrees Replace n with 32 We get 5400 degrees.
How many sides does a polygon with intiror angles of 5400 degrees?
It will have: (5400+360)/180 = 32 sides
Is it possible for the sum of the internal angles of a polygon to be 5400 degrees?
# Any exterior angle of a polygon corresponds to an interior angle, and their sum is 180 degrees. # If there are n sides (and therefore n vertices) then the sum of all the interior and exterior angles must be 180n. # The external angles of a polygon total 360 degrees, else it could not be a closed shape. # From the above three points, it follows that the sum of interior angles is given by 180n - 360. So, if there is an integer solution to 180n - 360 = 180(n - 2) = 5400, then the answer to your question is yes. 180(n - 2) = 5400 n - 2 = 30 n = 32 A polygon with 32 sides fulfills the criterion. That would be, hmmm, a triacontakaidigon, of course.
What is the size of each individual interior angle of a polygon having 464 diagonals showing key stages of work?
Providing that it is a regular polygon then let its sides be x: So: 0.5*(x2-3x) = 464 diagonals Then: x2-3x-928 = 0 Solving the equation: x = 32 sides Total sum of interior angles: 30*180 = 5400 degrees Each interior angle: (5400+360)/180 = 168.75 degrees
What is the number of sides in a regular polygon if the sum of the measure is 5400?
(5400+360)/180 = 32 sides
What is the sum of measures of angles in a 32-sided polygon?
(32-2)*180 = 5400 degrees
What is the sum of the measures of the interior angles of a 32-gon?
They add up to 5400 degrees
What is the degree of the angles in a figure with 32 equal sides?
(I am assuming you mean "What is the sum of the angles in a 32 sided polygon, expressed in degrees") The formula for this is: Sum of Interior Angles = 180(n-2) so the answer to your question is 180 times (32 minus 2) = 180 times 30 = 5400 degrees. (There is a very good description of this on the first hit in Google using "polygon angles" [without the quotes] as the search term): http://regentsprep.org/Regents/math/poly/LPoly1.htm
What is the measure of an exterior angle of a regular polygon in which the sum of the interior angle measure is 5400?
It has 32 sides and each interior angle measures 168.75 degrees and so 180-168.75 = 11.25 degrees which is the measure of each exterior angle
What is the measure of an interior angle of a regular pentagon rounded to the nearest tenth?
To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o
