726 / 13 = 55.84615384615385
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It's not possible. For two numbers to have a sum of 13, one would have to be even, that is, divisible by 2.
1, 7, 13, 91.
726 divided by 16 equals 45 with a remainder of 6.
39 is not divisible by 2, since it is odd. Looking at the next highest prime number 3, we see that it is divisible, so we divide by three until it is no longer divisible by 3: 39/3 = 13 13 is also prime, thus 3*13 is the prime factorization.
No, 117 is only divisible by: 1, 3, 9, 13, 39, 117.