2ab
12
36
2/3 and 3/4Looks like 12 here, so use form of one to convert both fractions to LCD form.4*2/4*3 and 3*3/3*48/12 and 9/12==========
Assume an additive expression.X5 + X3X3(X2 + 1)--------------------so,X3====Is the LCD
To find the least common denominator (LCD) of the numbers 98, 36, and 42, we first determine their prime factorizations: 98 = 2 × 7^2 36 = 2^2 × 3^2 42 = 2 × 3 × 7 The LCD is obtained by taking the highest power of each prime number present in the factorizations. This gives us: LCD = 2^2 × 3^2 × 7^2 = 4 × 9 × 49 = 1764. Thus, the LCD of 98, 36, and 42 is 1764.
LCD(3, 5, 4, 2) = 60
For 3/4 and 2/3 the LCD is 12.
lcd(6, 12, 16) = 48. 6 = 2 x 3 12 = 2^2 x 3 16 = 2^4 lcd = 2^4 x 3 = 48
60
15
12
I'm not sure you've written your question properly. As written I see: (¾)/4 and 2/3 But (¾)/4 = ¾ ÷ 4 = ¾ × ¼ = 3/16 → want lcd for 3/16 and 2/3 → lcm(16, 3) = 48 If you actually mean lcd for 3/4 (or three quarters) and 2/3 then: want lcd for 3/4 and 2/3 → lcm(4, 3) = 12
The LCD for 3/4 and 1/2 is 4.
12 is the LCD for 3 and 4.
the answer is 60
LCD(2, 3) = 6.
LCD of 1/3, 2/10 and 3/4 is 60