12
2ab
36
2/3 and 3/4Looks like 12 here, so use form of one to convert both fractions to LCD form.4*2/4*3 and 3*3/3*48/12 and 9/12==========
Assume an additive expression.X5 + X3X3(X2 + 1)--------------------so,X3====Is the LCD
To find the least common denominator (LCD) of the numbers 98, 36, and 42, we first determine their prime factorizations: 98 = 2 × 7^2 36 = 2^2 × 3^2 42 = 2 × 3 × 7 The LCD is obtained by taking the highest power of each prime number present in the factorizations. This gives us: LCD = 2^2 × 3^2 × 7^2 = 4 × 9 × 49 = 1764. Thus, the LCD of 98, 36, and 42 is 1764.
LCD(3, 5, 4, 2) = 60
For 3/4 and 2/3 the LCD is 12.
lcd(6, 12, 16) = 48. 6 = 2 x 3 12 = 2^2 x 3 16 = 2^4 lcd = 2^4 x 3 = 48
I'm not sure you've written your question properly. As written I see: (¾)/4 and 2/3 But (¾)/4 = ¾ ÷ 4 = ¾ × ¼ = 3/16 → want lcd for 3/16 and 2/3 → lcm(16, 3) = 48 If you actually mean lcd for 3/4 (or three quarters) and 2/3 then: want lcd for 3/4 and 2/3 → lcm(4, 3) = 12
The LCD for 3/4 and 1/2 is 4.
60
2ab
15
12 is the LCD for 3 and 4.
To find the least common denominator (LCD) of the fractions with denominators 3, 4, 2, and 9, we need to determine the least common multiple (LCM) of these numbers. The prime factorization of each number is: 3 (3), 4 (2^2), 2 (2), and 9 (3^2). The LCM takes the highest power of each prime: 2^2 and 3^2, resulting in 4 × 9 = 36. Therefore, the LCD of 3, 4, 2, and 9 is 36.
the answer is 60
LCD of 1/3, 2/10 and 3/4 is 60