2 x 2 x 3 = 12
3 x 3 x 3 = 27
2 x 2 x 3 x 3 x 3 = 108, the LCM
You need at least two numbers to find an LCM no matter what method you choose.
The LCM of 12 and 27 is 108
108
The LCM of the given two numbers is 48
Two or more numbers are normally needed to find the LCM
Since 36 is a multiple of 12, it is automatically the LCM, but if you insist... 2 x 2 x 3 = 12 2 x 2 x 3 x 3 = 36 2 x 2 x 3 x 3 = 36, the LCM
5 2 x 2 x 3 = 12 2 x 2 x 3 x 5 = 60, the LCM
If it's the lowest Common Multiple (LCM) of 12, 20, 24 and 32 that you're after, I think it's 480 (but my maths is a little rusty)
It is: 60
The LCM of the given two numbers is 48
They are: 12 and 360 respectively
Two or more numbers are normally needed to find the LCM
That's a lot of extra work for this problem but here goes. 3 is already prime so it doesn't really have a factor tree or prime factorization. The prime factorization of 4 is 2 x 2 which looks like this in a factor tree.42,23 and 4 have no common prime factors, so the LCM is their product, 12
12=22x3 15=3x5 So the LCM of 2, 12 and 15 is 22x3x5 = 60
2 x 2 x 3 = 12 3 x 7 = 21 2 x 2 x 3 x 7 = 84, the LCM
the prime factorization of 12 in exponents is 2 to the second power times 3
2 x 2 = 4 2 x 3 = 6 2 x 2 x 3 = 12, the LCM
Since 36 is a multiple of 12, it is automatically the LCM, but if you insist... 2 x 2 x 3 = 12 2 x 2 x 3 x 3 = 36 2 x 2 x 3 x 3 = 36, the LCM
22 x 3 = 12
To find the LCM of 12, 30, and 150, we need to decompose the numbers into their prime factors. The prime factorization of 12 is 2^2 * 3, the prime factorization of 30 is 2 * 3 * 5, and the prime factorization of 150 is 2 * 3 * 5^2. Now, we need to choose the common and uncommon prime factors with the highest exponent. The common prime factors are 2 and 3, and the uncommon prime factors are 5 and 2^2. Therefore, the LCM of 12, 30, and 150 is 2^2 * 3 * 5^2 = 300. [1]