169sin(37*) = 101.7067389 (round to 101.7)
*=degrees (function found on TI Calculators under "Angle") you can not do like that generally VpSIN(Wt
RMS stands for Root Mean Square. Power is calculated as V2/R where V is the voltage and R is the resistive component of a load, This is easy toi calculate for a DC voltage, but how to calculate it for a sinusoidal voltage? The answer is to take all the instantaneous voltages in the sine wave, square them, take the mean of the squares, then take the square root of the result. This is defined as the "heating effect voltage". For a sine wave, this is 0.707 of the peak voltage.
The sine wave represents 360 degrees or a full circle. As the satellite revolves 360 degrees around the earth in its orbit this is how it is represented on a flat surface.
RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source. Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".) But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
The phase angle varies from 0 to 360 degrees as the wave cycles.
rms values refer to "root mean square" mathematical values of the sine wave of electricity. This is essentially an "average" value of the voltage being measured as voltage in any circuit varies constantly.
To find the instantaneous voltage of a sine wave at a given angle, you can use the formula ( V(t) = V_{peak} \cdot \sin(\theta) ). For a peak voltage of 100 volts and at 150 degrees, convert 150 degrees to radians if necessary or use the sine function directly. The sine of 150 degrees is 0.5, so the instantaneous voltage is ( 100 \cdot \sin(150^\circ) = 100 \cdot 0.5 = 50 ) volts.
12.68V 3o * sin25 = 12.67854785
The instantaneous voltage at 90 degrees in a sinusoidal waveform is at its peak value, as this angle corresponds to the maximum point of the sine function. Mathematically, if the voltage is represented as ( V(t) = V_{\text{max}} \sin(\omega t + \phi) ), at 90 degrees (or ( \frac{\pi}{2} ) radians), the voltage is ( V(t) = V_{\text{max}} ). Thus, the instantaneous voltage is equal to the maximum amplitude of the waveform.
Because the instantaneous voltage of any AC is proportional to either one sine function of time or else to the sum of several sine functions of time. So anything that depends on the instantaneous voltage of an AC ... like for example the instantaneous current through a circuit energized by that AC ... will also be proportional to those same sines.
the answer is 5.6vp-p
On a sine wave, the voltage is equal to zero at every integer multiple of 180 degrees. This occurs at 0 degrees, 180 degrees, 360 degrees, and so on. These points represent the crossings of the waveform along the horizontal axis, where the sine function equals zero.
One cycle of the sine wave is equal to 360 degrees. In US the frequency of power is typically 60 Hz and hence one cycle is 1/60 of a second. Therefore you can calculate the degrees at any instant of time. If at zero degrees the voltage amplitude is zero, then at 90 degrees,which is 1/4 cycle, wave is at peak voltage. At 180 degrees it is at 1/2 cycle and zero voltage and then at 270 degrees it is 3/4 of the cycle and a peak negative voltage. Finally at 360 degrees the cycle is complete and the voltage is again zero.
We often see the peak and trough (maximum positive and maximum negative excursions) of the sine wave considered as points of momentarily constant voltage. Those points are at phase angles of 90 degrees and at 270 degrees.
The sine of 75 degrees is about 0.9659
It's not. The sine of 32 degrees is approximately 0.53. The sine of 59 degrees is approximately 0.86. For a definition of sine, see: http://en.wikipedia.org/wiki/Trigonometric_function .
10 Volts. ANSWER: ASSUMING a start when the voltage is at 0 and 0 degrees at 90 degrees is at maximum at 180 degrees is again at 0 v at 270 degrees is at the maximum negative potential and at 360 degrees is again at 0 v. the voltage is irrelevant in any case but it will follow these rules
The sine of 22.5 degrees is 0.383