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90 degrees 90 degrees
90 - 18 = 72 degrees.90 - 18 = 72 degrees.90 - 18 = 72 degrees.90 - 18 = 72 degrees.
Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees.
90 degrees C = 194 degrees F.
90 degrees and 90 degrees
Zero. If voltage starts at zero at zero degrees, it rises to peak voltage at 90 degrees. Voltage then reaches zero at 180 degrees and heads for negative peak voltage at 270 degrees and then back to zero at 360 degrees.
12.68V 3o * sin25 = 12.67854785
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
10 Volts. ANSWER: ASSUMING a start when the voltage is at 0 and 0 degrees at 90 degrees is at maximum at 180 degrees is again at 0 v at 270 degrees is at the maximum negative potential and at 360 degrees is again at 0 v. the voltage is irrelevant in any case but it will follow these rules
The product of the instantaneous voltage and the instantaneous current for a circuit or component.
90 degrees. In an AC circuit with a pure capacitance, the current leads the voltage by 90 degrees. This is because the current in a capacitor is proportional to the rate of change of voltage across it, leading to this phase relationship.
90 degrees
yes
In a capacitor, the current LEADS the voltage by 90 degrees, or to put it the other way, the voltage LAGS the current by 90 degrees. This is because the current in a capacitor depends on the RATE OF CHANGE in voltage across it, and the greatest rate of change is when the voltage is passing through zero (the sine-wave is at its steepest). So current will peak when the voltage is zero, and will be zero when the rate of change of voltage is zero - at the peak of the voltage waveform, when the waveform has stopped rising, and is about to start falling towards zero.
169sin(37*) = 101.7067389 (round to 101.7) *=degrees (function found on TI Calculators under "Angle") you can not do like that generally VpSIN(Wt
ICE current leads the voltage by 90 degrees.
because a coil is an inductor,for current leads voltage in an inductorAnswerIt doesn't! Current lags voltage in a coil. In a purely-inductive circuit, the current lags the supply voltage by 90 degrees. The reason for this is 'self inductance'. Whenever a current changes, a voltage is induced into the coil which opposes that change in current. The maximum self-induced voltage occurs when the rate of change in current is greatest. The greatest positive rate of change of a.c. current occurs when that current is passing through the zero axis of its waveform, so the greatest (negative) induced voltage occurs at thatsame point, which is one-quarter of the wavelength, or 90 degrees. In accordance with Kirchhoff's Voltage Law, the supply voltage must be in antiphase with the induced voltage. So when the peak induced voltage is negative, the peak applied voltage must be positive. Or, to put it another way, the peak value of the applied voltage must occur 90 degrees before the peak value of the current -so the current lags the applied voltage by 90 degrees.