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The instantaneous voltage at 90 degrees in a sinusoidal waveform is at its peak value, as this angle corresponds to the maximum point of the sine function. Mathematically, if the voltage is represented as ( V(t) = V_{\text{max}} \sin(\omega t + \phi) ), at 90 degrees (or ( \frac{\pi}{2} ) radians), the voltage is ( V(t) = V_{\text{max}} ). Thus, the instantaneous voltage is equal to the maximum amplitude of the waveform.
What else can I help you with?
How many degrees is an right angle?
90 degrees 90 degrees
What is supplement of 90 degrees?
The supplement of 90 degrees is the angle that, when added to 90 degrees, equals 180 degrees. Since 180 degrees minus 90 degrees equals 90 degrees, the supplement of 90 degrees is also 90 degrees. In other words, two angles that are supplementary add up to 180 degrees, and in this case, both angles are equal.
What is the measure of an angle who's complement is 18 degrees?
90 - 18 = 72 degrees.90 - 18 = 72 degrees.90 - 18 = 72 degrees.90 - 18 = 72 degrees.
Is it possible to have adjacent angles that are also vertical angles and why?
Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees. Yes. Because 90+90 = 180 degrees.
What is the supplement of a 90 degrees angle?
The supplement of a 90-degree angle is an angle that, when added to it, equals 180 degrees. Since 90 degrees is already half of 180 degrees, its supplement is 90 degrees. In other words, the supplement of a 90-degree angle is also 90 degrees.
What is the voltage at 90 degrees if the instantaneous voltage is 225v at 60 degree angle?
To find the voltage at 90 degrees given an instantaneous voltage of 225 V at a 60-degree angle, we can assume a sinusoidal function for the voltage. The voltage can be represented as ( V(t) = V_m \sin(\theta) ), where ( V_m ) is the maximum voltage. Since you provided the instantaneous voltage at 60 degrees, you can calculate the maximum voltage ( V_m ) using ( V_m = \frac{225}{\sin(60^\circ)} ). Then, to find the voltage at 90 degrees, you would evaluate ( V(t) ) at that angle, resulting in ( V(90^\circ) = V_m \sin(90^\circ) = V_m ).
What is the instantaneous voltage at 180 degrees for peak voltage of 150 volts?
Zero. If voltage starts at zero at zero degrees, it rises to peak voltage at 90 degrees. Voltage then reaches zero at 180 degrees and heads for negative peak voltage at 270 degrees and then back to zero at 360 degrees.
What is the instantaneous voltage of a sine wave at 25 degrees if its peak voltage is 30 V?
12.68V 3o * sin25 = 12.67854785
If the peak voltage of a sine wave is 100 volts then the instantaneous voltage at 150 and deg is volts?
To find the instantaneous voltage of a sine wave at a given angle, you can use the formula ( V(t) = V_{peak} \cdot \sin(\theta) ). For a peak voltage of 100 volts and at 150 degrees, convert 150 degrees to radians if necessary or use the sine function directly. The sine of 150 degrees is 0.5, so the instantaneous voltage is ( 100 \cdot \sin(150^\circ) = 100 \cdot 0.5 = 50 ) volts.
How many degrees are the current and voltage out of phase in a pure capacitive circuit?
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
What is the voltage at the 90 degree point of a sine wave with a maximum voltage of 10 volts?
10 Volts. ANSWER: ASSUMING a start when the voltage is at 0 and 0 degrees at 90 degrees is at maximum at 180 degrees is again at 0 v at 270 degrees is at the maximum negative potential and at 360 degrees is again at 0 v. the voltage is irrelevant in any case but it will follow these rules
What is powerful mean?
The product of the instantaneous voltage and the instantaneous current for a circuit or component.
What is the relationship between voltage and current in a pure inductive?
In a pure inductive circuit, the voltage and current are out of phase by 90 degrees. This means that the current lags the voltage, with the maximum voltage occurring a quarter cycle before the maximum current. As a result, the current reaches its peak value after the voltage, leading to a relationship where the instantaneous current is proportional to the rate of change of the voltage. Overall, this phase difference highlights the reactive nature of inductors in an AC circuit.
The phase angle between voltage and current in an a c circuit through a pure capacitance is?
90 degrees. In an AC circuit with a pure capacitance, the current leads the voltage by 90 degrees. This is because the current in a capacitor is proportional to the rate of change of voltage across it, leading to this phase relationship.
In a pure inductance circuit the current lags the voltage by what degree?
90 degrees
Solving problems on instantaneous voltage and current?
yes
A voltage wave has the equation e170sin and alpha. Calculate the instantaneous values of voltage for the following angles 30 degrees 60 deg?
To calculate the instantaneous voltage values for the given angles using the equation ( e(t) = 170 \sin(\alpha) ), where ( \alpha ) is in degrees, we substitute the angles into the equation: For ( \alpha = 30^\circ ): ( e(30) = 170 \sin(30^\circ) = 170 \times 0.5 = 85 , \text{V} ). For ( \alpha = 60^\circ ): ( e(60) = 170 \sin(60^\circ) = 170 \times \frac{\sqrt{3}}{2} \approx 147.2 , \text{V} ). Thus, the instantaneous voltages are approximately 85 V at 30 degrees and 147.2 V at 60 degrees.
