(x + 1)(x + 3)(x - 5)
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (0 plus or minus 2 times the square root of 5) divided by 5. x = 0.89442719 x = -0.89442719 If you had an x in there, it would come out nicer. 5x2 + x - 4 = (x + 1)(5x - 4)
15(p + 4)
15 x 45 = (15 x 40) + (15 x 5)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: -2 plus or minus 0.5 times the square root of 11. x = 0.3416876048223001 x = -3.6583123951777
4x2-17x-15) = 0 (4x+3)(x-5) = 0 Therefore: x = -3/4 or x = 5
(x + 1)(x + 3)(x - 5)
(4x+3)(x-5) = 0 x = -3/4 or x = 5
It is: 4x2-7x-15 when factored is (4x+5)(x-3)
4x2-7x-15 = (4x+5)(x-3) when factored
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
(2x + 3)(2x - 5)
(4x + 5)(x - 3)
(4x+5)(x-3)
4x2-7x-15 (4x+5)(x-3)
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (0 plus or minus 2 times the square root of 5) divided by 5. x = 0.89442719 x = -0.89442719 If you had an x in there, it would come out nicer. 5x2 + x - 4 = (x + 1)(5x - 4)
(4x + 5)(x - 3)