That doesn't factor neatly. Applying the quadratic equation, we find two real solutions:
(0 plus or minus 2 times the square root of 5) divided by 5.
x = 0.89442719
x = -0.89442719
If you had an x in there, it would come out nicer. 5x2 + x - 4 = (x + 1)(5x - 4)
Assuming the missing signs are pluses, that factors to 5(x + 10y + 8)
The prime factorization for 490 is 7x7x5x2= 490, or 7 to the power of 2 x 5x2
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (8 plus or minus 4i) divided by 5x = 1.6 + 0.8ix = 1.6 - 0.8iwhere i is the square root of negative one.
There aren't any common factors, which makes the GCF 1. This is meaningless to factor out, since it leaves the original equation. If you meant to write -5x7, that makes the common factor -x2 and leaves (5x5 + 13)
yes you do because 5 is a factor of 20 and so is 2 and 5x2=10 and 10 is a factor of 20
5x2 + 20x = 5x (x + 4)
x(5x - 4)
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
5x2 + 20 = 5*(x2 + 4) which cannot be factorised further.
assuming you meant 5x2+12x+4 (5x+2)(x+2)
(5x - 4)(x - 5)
5(x + 4)(x - 2)
(x - 2)(x - 2)(x - 1)
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
5x2 + 3x - 1 does not have rational factors.
5x2-46x+9 = (5x-1)(x-9)
False