That doesn't factor neatly. Applying the quadratic equation, we find two real solutions:
(0 plus or minus 2 times the square root of 5) divided by 5.
x = 0.89442719
x = -0.89442719
If you had an x in there, it would come out nicer. 5x2 + x - 4 = (x + 1)(5x - 4)
Assuming the missing signs are pluses, that factors to 5(x + 10y + 8)
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (8 plus or minus 4i) divided by 5x = 1.6 + 0.8ix = 1.6 - 0.8iwhere i is the square root of negative one.
The prime factorization for 490 is 7x7x5x2= 490, or 7 to the power of 2 x 5x2
There aren't any common factors, which makes the GCF 1. This is meaningless to factor out, since it leaves the original equation. If you meant to write -5x7, that makes the common factor -x2 and leaves (5x5 + 13)
yes you do because 5 is a factor of 20 and so is 2 and 5x2=10 and 10 is a factor of 20
5x2 + 20x = 5x (x + 4)
x(5x - 4)
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
5x2 + 20 = 5*(x2 + 4) which cannot be factorised further.
assuming you meant 5x2+12x+4 (5x+2)(x+2)
(5x - 4)(x - 5)
5(x + 4)(x - 2)
(x - 2)(x - 2)(x - 1)
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
5x2 + 3x - 1 does not have rational factors.
False
5x2-46x+9 = (5x-1)(x-9)