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The GCF is 6.

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Q: What is the gcf of 12p2 and 30q5?
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Related questions

What is the greatest common factor of 12p2 and 30q5?

The GCF is 6.


How do you factorize 3p4 - 12p2?

3 and p2 are both factors of each part of the binomial, so divide it from each part and see what you have left. (3p4 / 3p2) - (12p2 / 3p2) (3p2)(p2-4)◄


What is the perpendicular bisector equation of the line segment of p q and 7p 3q?

In its general form it works out as: 3px+qy-12p2-2q2 = 0Improved Answer:-Points:(p, q) and (7p, 3q)Slope: q/3pPerpendicular slope: -3p/qMidpoint: (4p, 2q)Equation: y-2q = -3p/q(x-4p) => yq = -3px+12p2+2q2Perpendicular bisector equation in its general form: 3px+qy-12x2-2q2 = 0


What is the GCF of the numbers 21 18 and 24?

The GCF is 6.


What is the GCF of 81 and 180?

The GCF is 9.


What is the gcf of 32 93 and 82?

The GCF is 4.


What is the gcf of 180 and 135 and 90?

The GCF is 30.


How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?

First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0


How do you work out and find the perpendicular bisector equation meeting the straight line segment of p q and 7p 3q?

First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector. Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p Slope of perpendicular bisector: -3p/q Equation: y -2q = -3p/q(x -4p) y = -3px/q+12p2/q+2q Multiply all terms by q to eliminate the fractions: qy = -3px+12p2+2q2 Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0


What is the GCF of 10a2 40a?

50


GCF of 3 and 30?

The GCF is: 1


What is the GCF of 81and108?

The GCF is 27.