3 and p2 are both factors of each part of the binomial, so divide it from each part and see what you have left.
(3p4 / 3p2) - (12p2 / 3p2)
(3p2)(p2-4)◄
2x2x2x2x3x3x11 =) Go to (http://www.purplemath.com/modules/factnumb.htm) to learn how to factorize
2(5v + 6u)
42
It is: 2(11x+3) when factorized
5x + 5y = 5(x+y)
The GCF is 6.
The GCF is 6.
The noble gas figure for Sulfur (S) is [Ne] 3s2 3p4.
The atomic number for sulfur is 16. That means that its electron configuration is 1s2 2s2 2p6 3s2 3p4. This can be shortened to [Ne] 3s2 3p4, which shows you that 3s2 3p4 is how sulfur's electron configuration ends.
Factorize others as you would have them factorize you.
6ab-3b factorize = 3
Sulfur is the group 16, period 3 chemical element. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p4. Another way to write this is [Ne] 3s2 3p4 since the initial portion of the configuration is the same as neon's.
[Ne] 3s2 3p4See the notes on the Noble Gas configuration of Barium.Noble_gas_notation_for_barium
(Ne) 3s2 3p4
2x2x2x2x3x3x11 =) Go to (http://www.purplemath.com/modules/factnumb.htm) to learn how to factorize
[Ne] 3s2 3p4
[Ne] 3s2 3p4