3 and p2 are both factors of each part of the binomial, so divide it from each part and see what you have left.
(3p4 / 3p2) - (12p2 / 3p2)
(3p2)(p2-4)◄
2x2x2x2x3x3x11 =) Go to (http://www.purplemath.com/modules/factnumb.htm) to learn how to factorize
2(5v + 6u)
42
It is: 2(11x+3) when factorized
5x + 5y = 5(x+y)
The GCF is 6.
The GCF is 6.
The atomic number for sulfur is 16. That means that its electron configuration is 1s2 2s2 2p6 3s2 3p4. This can be shortened to [Ne] 3s2 3p4, which shows you that 3s2 3p4 is how sulfur's electron configuration ends.
[Ne] 3s2 3p4
Sulfur is the group 16, period 3 chemical element. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p4. Another way to write this is [Ne] 3s2 3p4 since the initial portion of the configuration is the same as neon's.
[Ne] 3s2 3p4See the notes on the Noble Gas configuration of Barium.Noble_gas_notation_for_barium
Factorize others as you would have them factorize you.
6ab-3b factorize = 3
(Ne) 3s2 3p4
[Ne] 3s2 3p4
[Ne] 3s2 3p4
2x2x2x2x3x3x11 =) Go to (http://www.purplemath.com/modules/factnumb.htm) to learn how to factorize