The smallest positive 4-digit multiple of seven is 1,001.
-8
24
The least common multiple of 4, 5, and 8 is 40.
81
the least common multiple of 4 and 8 is 8. it's that easy. if you don't belive me do the math because i did. because, look at this. 4: 4, 8, 12, 16, 20 AND 8: 8, 16, 24, 32, 40 so the least common multiple is 8.
992
96
The largest 4 digit number in base 8 is 77778 (= 409510).
A number is a multiple of 4 if the last 2 digits are a multiple of 4 The 10s digit is even and the last digit is 0, 4 or 8 The 10s digit is odd and the last digit is 2 or 6 A number is a multiple of 8 if the last 3 digits are a multiple of 8 The 100s digit is even and the last 2 digits are a multiple of 8 The 100s digit is odd and the last 2 digits are 4 times an odd number
8*number = 3-digit number start by knowing basic times tables 1 through 9 8, 16, 24, 32, 40, 48, 56, 64, 72 8*100 = 800 8*30 = 240 8*130 = 1040 8*20 = 160 8*120 = 960 8*4 = 32 8*124 = 992 the largest 3-digit number that is a multiple of 8 is 992
18
When the tens digit is even and the units digit is 0, 4 or 8 or the tens digit is odd and the units digit is 2 or 6.
The largest 4-digit even number is 9998. It is formed by using the highest digits available (9, 9, 9, and 8) while ensuring that the last digit is even, which in this case is 8. Therefore, 9998 is the largest 4-digit number that meets the criteria of being even.
To find a 4-digit number that is divisible by both 8 and 9, we need to find a number that is a multiple of the least common multiple of 8 and 9, which is 72. Starting from the smallest 4-digit multiple of 72, which is 1008, we can find the next number by adding 72 until we reach a 4-digit number. Therefore, the smallest 4-digit number that is divisible by both 8 and 9 is 1008.
738
8 x 12 which equals 96
All multiples of their LCM is divisible by them. lcm(8, 7, 6, 5, 4, 3, 2, 1) = 840 therefore need the largest multiple of 840 which is a 3-digit number = 840 x 1 = 840.