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The sequence appears to follow the pattern of ( n^3 - 1 ) for ( n = 1, 2, 3, 4, 5 ). Specifically, the numbers correspond to ( 1^3 - 1 = 0 ), ( 2^3 - 1 = 7 ), ( 3^3 - 1 = 26 ), and ( 4^3 - 1 = 63 ). Therefore, the next number would be ( 5^3 - 1 = 124 ). Thus, the next number in the sequence is 124.
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What is the pattern of 0-7-26-63-124?
The pattern in the sequence 0, 7, 26, 63, 124 involves the formula ( n^3 - n ), where ( n ) is a positive integer starting from 1. Specifically, for each ( n ): ( 1^3 - 1 = 0 ) ( 2^3 - 2 = 7 ) ( 3^3 - 3 = 26 ) ( 4^3 - 4 = 63 ) ( 5^3 - 5 = 124 ) Thus, the next number in the sequence would be ( 6^3 - 6 = 210 ).
Is there any factors o?
No. To be a factor of a number, that number has to be divisible by the number you are finding factors for. True, 0 can be divided by 0, but a factor has to be a positive number. 0 is not positve nor is it negitive.
Which is the smallest single digit number 0 or 1?
0.
If a number is divisible by another number when the is 0. then what is that blank?
remainder
Let z be a complex number such that Imz 0 Prove that Im1z 0?
If the imaginary part of z is 0, then z is simply a real number and if you multiply by 1 which is the identity in multiplication of real numbers, you of course will still have a real number with imaginary part 0
