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Why is 195 and 190 divisible by 5?
Because any number ending with 5 or 0 is divisible by 5 except of course 0 by itself
Which of the numbers is divisible by 2 8639752999742681200023?
Any number that ends in an even number (0, 2, 4, 6, 8) is divisible by 2.
Is there any factors o?
No. To be a factor of a number, that number has to be divisible by the number you are finding factors for. True, 0 can be divided by 0, but a factor has to be a positive number. 0 is not positve nor is it negitive.
What is a 10 digit number when is divisible by 10 gives remainder 9 and when it is divisible by 9 it gives remainder 8 and so on what is that no.?
If a number is divisible by 10 it cannot give any remainder other than 0. That is what "divisible by" means!
How do you use divisibility rules to find at least for factors of a number?
Take the number 3336. You know it's divisible by 1 because everything is. You know it's divisible by 2 because it's even. You know it's divisible by 3 because the digits add up to a multiple of 3 and you know it's divisible by 4 because the last two digits are divisible by 4. So you've found at least four factors: 1,2,3 and 4.
