P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2)
where n1,n2=0,1,2,....n n1+n2<=n
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just like factoring any other trinomial.
PMF Legal Blog - 2010 International Insolvency July 2013 3-9 was released on: USA: 2 July 2013
Yes.
A trinomial
coefficient