(x + 3)(x - 2)
It's not enough to copy the question off the test. If you don't tell us what the trinomial is, we can't factor it for you.
(t - 15)(t + 3)
just make the trinomial easier to factor. ex -x2 + 3x + 4 ... most books don't teach you how to factor when a leading term is negative. ... so -1(x2- 3x- 4) ... now factor again ignoring the -1 -1(x - 4)(x + 1)
That's not a trinomial, but it factors to x(x + 19)
That trinomial is unfactorable (the roots are not integers).
x2-5x-36 = (x-9(x+4) when factored
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
(y10 + 2y5z3 + 4z6)
x2-5x+4 = (x-1)(x-4) when factord
(x + 3)(x - 2)
(x + 5)(x - 3)
A factor of a perfect square trinomial is eithera number that is a factor of each term of the trinomial,a binomial that is a factor of the trinomial, ora product of the above two.For example, consider 4x2 + 8x + 4It has the factors2 or 4,(x + 1) or2x+2 = 2*(x+1) or 4x+4 = 4*(x+1)
That is the linear part.
Choose any number except zero for the first factor. Then divide 90 by this factor to get the second factor.
Yes.
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