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Can two numbers have the same prime factorization?

No, multiplying a set of numbers can only come out as one product. Therefore, two numbers having the same prime factorization is impossible.


What is the prime factorization for two?

Two is already prime. No factorization.


How can you determine from the prime factorization whether the least common multiple of two numbers is the product of the numbers?

If the prime factorizations have no factors in common, the LCM is the product of them.


What is the prime factorization of 49 in two two ways?

72 = 49 7 x 7 = 49


What does the word prime factorization?

That's two words and it means to break down a composite number into the product of its prime factors.


What is the prime factorization of two?

2 is already prime, no factorization is required.


What is prime factorization of 92 in two ways?

2 x 2 x 2322 x 231


What are two prime numbers that would generate 400?

There are no two prime numbers that would generate 400. The prime factorization of 400 is 2^4 * 5^2, which means it can be expressed as the product of two powers of primes, but not as the product of two distinct prime numbers.


How can you determine from the prime factorization whether the least common multiple of two numbers is the product of the number?

If the two numbers have no common prime factors, the LCM will be the product of the numbers.


What are the pairs of prime factorization with a difference of 2 in 100?

The prime factorization of 100 is 2x2x5x5. There are no pairs of prime factorization with a difference of two in the number 100.


Prime factorization of 1 4?

The prime factorization of 14 is 2 x 7. Prime factorization is multiplying two prime numbers by each other to get the original number.


How many ways 14630 can be written as product of two numbers?

To determine how many ways 14630 can be expressed as a product of two numbers, we first need its prime factorization. The prime factorization of 14630 is (2 \times 5 \times 1463). The number of divisors can be calculated from the exponents of the prime factors; since (2^1, 5^1, \text{ and } 1463^1) each have an exponent of 1, the total number of divisors is ((1+1)(1+1)(1+1) = 2 \times 2 \times 2 = 8). Each pair of divisors ( (d, \frac{14630}{d}) ) gives a product of 14630, so the number of unique pairs is half of the total number of divisors, leading to 4 ways to express 14630 as a product of two numbers.