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1215 is divisible by 3 because its digits add up to a multiple of 3. That leaves 405.

405 is divisible by 3, leaving 135.

135 is divisible by 3, leaving 45.

45 is divisible by 3, leaving 15.

15 is divisible by 3, leaving 5.

5 is divisible by 5 because it ends in 5.

3 x 3 x 3 x 3 x 3 x 5 = 1215

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Q: What is the prime factorization using divisibility rules for 1215?
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