6, 12, 18, 24, 30,
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
A. 12 and 18
3, 6, 9, 12, 15, 18 4, 8, 12, 16, 20, 24 6, 12, 18, 24, 30, 36 Common multiples include 12, 24, 36, 48, 60, 72
The hcf is 12
Each number is decreasing by 3. The next numbers in the sequence would be -18, -21, -24, -27, -30.
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
It is 30; the first, third, and fifth numbers form the sequence 12, 18, 24. The second, fourth, and sixth numbers follow the sequence 11, 14, 17. Logically, the seventh number must be 24 + 6, so 30.
Think it's 30...then 20
Next is 18. The polynomial rule is Un = (-5n4 + 74n3 - 301n2 + 478n - 24)/24 for n = 1, 2, 3, ...
U1 = 27 U{n+1} = U{n} - 3
39. The rule here is starting with the number 9, add (-6 + sequence number * 6). 9 + (-6) = 3 3 + 0 = 3 3 + 6 = 9 9 + 12 = 21 21 + 18 = 39 39 + 24 = 63
10. Then 12, 14, 16, 18, 20, 22, 24, etc.
That number sequence is already in ascending order as integers. 1/3, 3/8, 1/2, 3/4 as fractions 8/24, 9/24, 12/24, 18/24
t(n) = 6n
LCM(12, 18, 24) = 72; GCF(12, 18, 24) = 6.
The answer depends on where in the sequence the missing number is.The sequence could be:-108, 12, 24, 36, 96, 19212, 36, 24, 36, 96, 19212, 24, 18, 36, 96, 19212, 24, 36, 54, 96, 19212, 24, 36, 96, 180, 19212, 24, 36, 96, 192, 252So take your pick. And next time, please try to specify where the missing number should be!