Exponents are not needed but it would be 21 x 51 x 111
Start with the prime factorization.2 x 5 x 11 = 110Any number with three distinct prime factors has eight factors in total. Once we add in 1, we have them all.All Factors of 110:1, 2, 5, 10, 11, 22, 55, 110
To find the LCM of 110 and 20, you first need to break them up into their prime factors: 110 = 2x5x11 20 = 2x2x5 The next step is to identify the HCF. In this case the HCF will be 2x5 = 10. To find the LCM you multiply the numbers together and divide by the HCF: 110x20/10 = 220. Thus the LCM of 110 and 20 is 220.
The least common multiple (LCM) of 2, 11, and 5 is the smallest multiple that all three numbers share. To find the LCM, you first need to find the prime factors of each number: 2 = 2, 11 = 11, and 5 = 5. Then, you multiply the highest power of each prime factor to find the LCM: LCM(2, 11, 5) = 2 * 11 * 5 = 110. Therefore, the least common multiple of 2, 11, and 5 is 110.
1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 121, 242, 275, 550, 605, 1210, 3025, 6050 2, 5 and 11 are prime.
It is: 2*5*11 = 110
The tree for 110 is: 55 & 2. 2 is prime. Then 5 & 11. They are both prime.
2 x 5 x 11 = 110
2 x 5 x 11 = 110
2×5×11
110 55,2 11,5,2
110 = 2 x 5 x 11
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110
2 x 5 x 11 = 110
110 = 21 x 51 x 111
110 55,2 11,5,2 2 x 5 x 11 = 110
55 3*55 = 165 2*55 = 110