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What is the value of moment of inertia of ellipse about its centroidal axis?
Wiki User
∙ 13y ago
If an ellipse has a radius A long the x-axis and B along the y-axis (A > B) then the moment of inertia about the x-axis is 0.25*pi*ab^3
Wiki User
∙ 7y ago
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What is the value of moment of inertia of ellipse about x-Axis?
Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis. Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis.
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Moment of inertia is a cross sectional property that gives the engineer an indication of the stiffness of a particular shape value can used to?
find the strength of the member subject to bending or shear. Moment of inertia is used to find radius of gyratia or flexural regidity so that member strength flexural stress is found
What is the moment of inertia of a cube with uniform density about any edge?
Think of it as the difference in moment of inertias for two solid cubes. Calculate the moment of inertia of a solid cube with dimensions equal to the inner dimensions of your hollow cube. Then calculate the moment of inertia of a solid cube with dimensions equal to the outer dimensions of your hollow cube. Subtract the moment of inertia of the inner dimensions from the moment of inertia of the outer dimensions to get the moment of inertia of what's left. Same concept applies to finding the area of a thin-walled circle. Outer area - inner area = total area. Outer moment of inertia - inner moment of inertia = total moment of inertia. This approach won't work however if you're considering hollow shell - a cube with walls of zero thickness. If the axis of rotation goes through the cube center, perpendicular to one of its walls, first calculate moment of inertia of the wall that the axis passes through (let's call it Ia). For all equations below d equals surface density(mass per unit of area) and a is length of cube's side. Ia= d * a4 / 6 Then you have to calculate moments of inertia of four walls parallel to the axis. This will be Ib=4 * Iwall=4*d*a4/3. Total moment of the shell will be then: I=2*Ia+Ib=1.5*d*a4. If the axis is through the center and ┴ one face, I = (m/6)*[a² - (a-t)²], or I = (m/6)(2at - t²) for any value of t, however small. Source: CRC Std Math Tables
In the flywheel experiment how would you provide a value for the moment of inertia of a toothed gear wheel?
For flywheel: J= ?/32 × d4 ×?steel × lYou can obtain a more accurate value by considering every single component ie. each gear, each boss etcThe apparent moment of inertia is J'=J/R2R is gear ratio ,?steel is 8000 kgm3 and obviously d is diameter, l is length.. ..
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If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.An ellipse has no sides and no corners. It is a smooth, continuous function, with no discontinuities. (This answer depends on your definition of a side - if you mean that a side is a straight line, then it is true, if not, then an ellipse has one side and no corners.)
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