16:1, 2, 4, 4, 8, 1625:1,5, 5, 2560: 1,5,6,10,12,60Greatest Common factor ='s 1
The numbers that can be divided exactly into 16 are 1 2 4 8
24's factors are 1x24 2x12 3x8 4x6 or,1,2,3,4,6,8,12,and 24
The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24 For them to be common, they need to be compared to another set of factors.
(5x + 6)(x + 4)
8, 16, 24 and so on.
Sales=16 VC=8 Cont=8 [(16-8)] Cont margin=16/8=20% Trust this helps S
4, 8, 12, 16, 20, 24 and so on.
5
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100,104,108,
The final velocity can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Given the initial velocity of 24 m/s, acceleration of 2 m/s^2, and time of 8 seconds, you can substitute these values into the formula to find the final velocity. Final velocity = 24 m/s + (2 m/s^2 * 8 s) = 24 m/s + 16 m/s = 40 m/s. Therefore, the final velocity of the car is 40 m/s.
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
No 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88. 81 is not a multiple of 8.
1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.
Assuming the shape is a triangle, the area is 151.65 sq in. A = √[s(s - a)(s - b)(s - c)], where s = the semi-perimeter, a, b, and c are the side lengths. Let a = 19, b = 16, c = 24, and s = (19 + 16 + 24)/2 = 29.5 So we have, A = √[s(s - a)(s - b)(s - c)] = √[29.5(29.5 - 19)(29.5 - 16)(29.5 - 24)] = 151.65 in2.
16:1, 2, 4, 4, 8, 1625:1,5, 5, 2560: 1,5,6,10,12,60Greatest Common factor ='s 1
The two numbers that have a least common multiple (LCM) of 24 and a highest common factor (HCF) of 2 are 8 and 12. The LCM of two numbers is the smallest number that is a multiple of both numbers, while the HCF is the largest number that divides both numbers without leaving a remainder. In this case, 8 and 12 have an LCM of 24 because 24 is the smallest number that is a multiple of both 8 and 12, and they have an HCF of 2 because 2 is the largest number that divides both 8 and 12 without leaving a remainder.