The positive integer factors of 539 are 1, 7, 11, 49, 77, and 539
539 = 1 x 539539 = 7 x 77539 = 11 x 49OR prime factorization: 7 x 7 x 11
4851 = 3 x 1617 1617 = 3 x 539 539 = 7 x 77 77 = 7 x 11 Full factorisation is thus 3 x 3 x 7 x 7 x 11
3x
3x2 - 3x - 60 = 3(x2 - x - 20) = 3(x2 - 5x + 4x - 20) = 3(x[x - 5] + 4[x - 5]) = 3(x + 4)(x - 5)
539 x 2,000,000,000 = 1,078,000,000,000
The positive integer factors of 539 are 1, 7, 11, 49, 77, and 539
1 x 539, 7 x 77, 11 x 49.
1 x 539, 7 x 77, 11 x 49
539 = 7 x 7 x 11
539 49 = 72 77 = 7 x 11 lcm = 72 x 11 = 539
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
- 3x - Xsame as- 3x + (- X)= - 4X=====
539 = 1 x 539539 = 7 x 77539 = 11 x 49OR prime factorization: 7 x 7 x 11
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)