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The positive integer factors of 539 are 1, 7, 11, 49, 77, and 539
539 = 1 x 539539 = 7 x 77539 = 11 x 49OR prime factorization: 7 x 7 x 11
4851 = 3 x 1617 1617 = 3 x 539 539 = 7 x 77 77 = 7 x 11 Full factorisation is thus 3 x 3 x 7 x 7 x 11
3x
3x2 - 3x - 60 = 3(x2 - x - 20) = 3(x2 - 5x + 4x - 20) = 3(x[x - 5] + 4[x - 5]) = 3(x + 4)(x - 5)