1) 3x-17=0 3x=17 x=17/3 2) 3x-25=0 3x=25 x=25/3
x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
3x+12 = 18 3x = 18-12 3x = 6 x = 2
-31
3x = (96-75) 3x = 21So X = 7
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x2 + x = x*(3x + 1)
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
If the angles are x, 3x and 3x+5, the following equation gives x x+3x+(3x+5)=180 -> x =25, and in degrees the angles are 25, 75 and 80.
(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
x-2=3x+1 x=3x+1+2 x-3x=3 -2x=3 x=-3/2
1) 3x-17=0 3x=17 x=17/3 2) 3x-25=0 3x=25 x=25/3
If that's -3x, the answer is (x - 7)(x + 4) If that's +3x, the answer is (x + 7)(x - 4)
3x - 5x + x = -x