Divide each number by their GCF, which is 18. 108/126 = 6/7
The following: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
List the integers that will divide into 42 evenly with no remainder.
The number one.
Divide 7 into 291. If it comes out evenly, it's a factor. It doesn't, so it's not.
6
13
6
18
You need to divide it by 6/7.
yes
In the sequence 20 5 30 6 42 7, the rule is divide by 4 then multiply by 6, divide by 5 then multiply by 7, divide by 6 then multiply by 8 since each time the number by which you multiply or divide by increases by 1. Since the last multiplication was by 7, we know the next will be by 8. Therefore, the answer you get for the next number in the sequence is 56 (7x8=56).
Nope... to check if a number will divide by 3 - add the digits of the number together. In this case, 6+7+7=20, which will not divide exactly by three.
1
56205 (divide 20 by 4)30 (multiply 5 by 6)6 ( divide 30 by 5)42 (multiply 6 by 7)7 (divide 42 by 6)....as you can see the pattern switches from division to multiplication. From this pattern the next number will be mulitplying 7 by 8. so the next number is 56.
-6 > - 7 since we divide to both sides with a positive number such as 2 is, the sign does not change, so that -6/2 > -7/2 -3 > -3.5
my umber is between 1 and 25 When you divide my number by 7, the remainder is 3 when you divide my number by 6, the remainder is 5 when you divide my number by 5, the remainder is w what's my number?