I would do it like this though I'm sure there are other ways: There are 10 multiples of 3 every 30 (3,6,9,12,15,18,21,24,27,30). There are (1000/30)= 33 lots of 30 in 1000 Therefore there are (10 x 33)=330 multiples of 3 which brings us up to 990 (330x3 =990) Then there are 3 more multiples of 3 993, 996,999 This makes the total 333 multiples of three between 1 and 1001
No. A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. Factors go into numbers, numbers go into multiples.
The first 5 multiples of 135 are: 135, 270, 405, 540, and 675.
5 of them.
6, 12, 18, 24, 30, 36, 42, 48, 54, 60 and keep adding 6 till you get to 9996.
All multiples of 12, such as 120, 600, 660.
There are 143 such numbers, too many to list.
All of its multiples from 3 to 999
Multiples of 25 up to 1000 are: 25;50;75;100;125;150;175;200;225;250;275;300;325;350;375;400;425;450;475; 500;525;550;575;600;625;650;675;700;725;750;775;800;825;850;875;900;925;950;975;1000
To find all the multiples of 30 up to 1000, we can start by dividing 1000 by 30, which equals 33 with a remainder of 10. This means the last multiple of 30 within 1000 is 990. So, the multiples of 30 up to 1000 are 30, 60, 90, 120, all the way up to 990.
The multiples of 3 up to 30 are: 3,6,9,12,15,18,21,24,27,30.The multiples of 5 up to 30 are: 5,10,15,20,25,30.The only common multiples are 15 and 30.The LCM is: 30
30, 60, 90, 120, 150, 180, 210 and just keep adding 30 until you get to 990
If you mean the LCM (lowest common multiple) of 2 and 1000, the answer is 1000.If you mean the factors of 2 and 1000, then they are as follows.Factors of 2- 1,2.Factors of 1000- 1,2,4,5,8,10,100,125,200,250,500,1000.Therefore, the HCF (highest common factor) of 2 and 1000 is 2.
No odd numbers are multiples of 4.
They are members of the set of numbers of the form 6*k where k is a positive integer which is less than 167.
250
35, 42, 49