3(2y + 3)(y + 2)
It is a quadratic expression in the variable x.
6y2 - 36 = 6ySubtract 6y from each side:6y2 - 6y - 36 = 0Divide each side by 6:y2 - y - 6 = 0Factor the expression on the left side:(y + 2) (y - 3) = 0The equation is a true statement if either factor is = 0.y + 2 = 0 ==> y = -2y - 3 = 0 ==> y = 3
There is no rational factorisation of 6y2 + 19y - 13 The roots are [-19 +/- sqrt(673)]/12 which are -3.74519 and 0.57852
It is: (6y+1)(y-5) when factored
2(3y + 1)(y - 2)
3y^2(5y + 2)
60
20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
6y2+17y-14 = (2x+7)(3x-2) when factored
There's no solution, because that's not an equation or any kind of question.It's just an expression, with a value that depends on what ' y ' is, and canchange in an instant whenever ' y ' changes.If that expression were equal to something, then we'd have to find the valueof ' y ' that could make it a true statement, and thatwould be the solution.
6(y + 3)(y - 3)