If a number is divisible by both three and four, it's divisible by twelve.
If, when divided by 3, it leaves no remainder. Also, if you add the individual numbers up and that number is divisible by three, the larger one is as well. Example: 12345 adds up to 15. 15 is divisible by three. So is 12345.
Every number is divisible by any non-zero number. 527 is not evenly divisible by 3.
yes, 12 and 28 are both divisible by 4 resulting in a whole number answer.
Every number is divisible by any non-zero number. Furthermore, 5835 is evenly divisible by 3.
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.
If a number is divisible by both three and four, it's divisible by twelve.
If the sum of the digits can be divided by 3. 93 is divisible by 3 because 9+3=12 we know 12 is divisible by 3 because 1+2=3 so the number is divisible by 3.
Add up the digits of the number. If the sum is divisible by 3, then the number itself is divisible by 3. Ex: Is 781 divisible by 3? 7+8+1=16 16 is not divisible by 3 so neither is 781 Is 903 divisible by 3? 9+0+3= 12 12 is divisible by 3 so 903 is divisible by 3
12 is the Lowest Common Multiple
Yes. 1 + 2 + 9 = 12 12 is divisible by 3. If the sum of the digits of a number are divisible by 3, then the whole number is divisible by 3. 129 is a composite number because it divisible by a factor other than 1 and itself.
Yes.
Yes, the integers in the number add up to a multiple of 3, 12. 2+3+7=12, therefore the number is divisible by 3.
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
12
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9