5, 10, and 20 are all multiples of 5 and factors of 20.
No. A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. Factors go into numbers, numbers go into multiples.
There are infinetly many numbers which have 2 and 5 as their factors. Some examples are 10, 20, 30, 40, etc. 2 and 5 both are prime numbers and their common multiples are the multiples of 2 x 5 = 10. So all the multiples of 10 have 2 and 5 as their factors. However if consider 2 and 5 as the only two proper factors, then the required number is 10.
10 20 30 40 50 60 70 80 90 100
It's false because there are other numbers ending 0 being multiples of 5.
There are three numbers between 10 and 50 which are divisible by both 3 and 5. All numbers that are multiples of 3 and 5 are the multiples of the lowest common multiples (lcm) of 3 and 5 which is 15. The multiples of 15 between 10 and 50 are {15, 30 and 45}, thus there are 3 numbers.
Multiples. The numbers 10, 15 and 20 are multiples of 5.
Multiples of 10.
Multiples of 10
5, 10, 15, 20
5, 10, and 20 are all multiples of 5 and factors of 20.
Numbers which are the factors of thirty and multiples of five are 5, 10, 15 and 30.
Numbers ending in zero are all multiples of 10, and therefore also are multiples of 2 and 5.
Multiples of 10.
5, 10, 25, 50
Well, honey, common multiples of 5 and 10 are numbers that both 5 and 10 can divide evenly into. So, grab your calculator and start counting by 10s until you hit a number that is also divisible by 5. Spoiler alert: the first few common multiples are 10, 20, 30, 40... you get the idea. Happy math-ing!
The common multiples of 2 and 5 are 10, 20, 30, 40, etc.In detail:A common multiple is a number divisible by both (or all) numbers: 2 and 5, here.Knowing that all numbers divisible by 2 have a 0, 2, 4, 6, or 8 in the ones place combined with the knowledge that all numbers divisible by 5 end with 0 or 5 (excluding 0 in both cases), we can say the only multiples of each number that are common to both are numbers that end with 0.Another way of analyzing this problem is to say that both 5 and 2 are factors. 10 is clearly a multiple of 5 and 2 because 2(5)=10. Any number divisible by 10 is thus also divisible by 2 and 5. All numbers divisible by 10 end in 0. Thus, a number ends in 0 if and only if it is divisible by 2 and 5.Answer: Common multiples of 2 and 5 end with zero.