45 Divide by three. 15,3 Divide by three. 5,3,3 Stop.
36 18,2 9,2,2 3,3,2,2 2 x 2 x 3 x 3 = 36
If you construct them correctly, factor trees always work to determine the prime factorization of a number. Once you compare the prime factorizations of two or more numbers, it is relatively easy to find the greatest common factor of them from there.
44 Divide by two. 22,2 Divide by two. 11,2,2 Stop. 2 x 2 x 11 = 44
100 50,2 25,2,2 5,5,2,2
23 is already prime.
456
all the numbers are prime numbers therefore the prime factorization of 2*2*5*11=2*2*5*11
13 is already prime. Just write it down.
18 9,2 3,3,2
60 30,2 15,2,2 5,3,2,2
Divide by 3 or 5. 3 x 5 = 15
As a product of its prime factors: 2*2*2*5*19 = 760
Yes, 2x2x2x5 can be written in prime factorization as 2^3 x 5. In prime factorization, we break down a number into its prime factors. Here, 2 is a prime number and appears three times, so we write it as 2^3. The number 5 is also a prime number and appears once, so we simply write 5.
It is: 2*2*5*7 = 140 by dividing it by each prime number that has no remainder
Multiply the factors. They should equal the original number.
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2