LCM(5, 38) = 190.
5 is not divisible by 1260. 1260 is divisible by 5 because 1260 is a multiple of 5.
1, 2, 4, 5, 8, 10, 16, 19, 20, 38, 40, 76, 80, 95, 152, 190, 304, 380, 760, 1520
625 Is divisible by 5
No, only numbers that end in 5 or 0 are divisible by 5.
-190
Yes and it is 195/5 = 39
Yes
Multiples of 195.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
1, 2, 5, 10, 19, 38, 95, 190.
It is a question. And the answer to the question is "yes".
195 is composite because it is divisible by 5.
No, 190 is not evenly divisible by 4.
195
You can find a common denominator by multiplying together the denominators of your fractions. For example, try 13 * 15 = 195 (you don't need to use the 5 because anything divisible by 15 will also be divisible by 5). You know that 195 is divisible by 13 and 15 (because those are the two numbers you multiplied together to get it), and by 5 because 195 ends in a 5. Now convert the numerators so you have equivalent fractions: 5/13 = 75/195 2/5 = 78/195 7/15 = 91/195 So 7/15 is the greatest. But sometimes it's easier just to convert your fractions to decimals by dividing the numerators by the denominators: 5/13 = .38461538461538 2/5 = .4 7/15 = .46666666666666 (repeating forever)
if all the digits add up to a number divisible by 3 like 195 195= 1+9+5= 15...15/3=5 so it is divisible by 3