585 is divisible (without remainders) by: 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585.
39, 78, 117, 195, 312 and 936 are divisible by three.
195 / 5 = 39
esentialy all mutiples of 15 are also divisble by 5 and 3 15 30 45 60 75 90 105 120 135......
If it has any factors in addition to '1' and 195, then it's composite. Since it ends with a 5, we can see just by looking at it that it's divisible by 5, and that's all we need to know. It may have even more factors, but we can already be sure that it's a composite number.
Multiples of 195.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
195 is composite because it is divisible by 5.
Because any number ending with 5 or 0 is divisible by 5 except of course 0 by itself
You can find a common denominator by multiplying together the denominators of your fractions. For example, try 13 * 15 = 195 (you don't need to use the 5 because anything divisible by 15 will also be divisible by 5). You know that 195 is divisible by 13 and 15 (because those are the two numbers you multiplied together to get it), and by 5 because 195 ends in a 5. Now convert the numerators so you have equivalent fractions: 5/13 = 75/195 2/5 = 78/195 7/15 = 91/195 So 7/15 is the greatest. But sometimes it's easier just to convert your fractions to decimals by dividing the numerators by the denominators: 5/13 = .38461538461538 2/5 = .4 7/15 = .46666666666666 (repeating forever)
if all the digits add up to a number divisible by 3 like 195 195= 1+9+5= 15...15/3=5 so it is divisible by 3
No - 195/2 = 97.5
Yes. 195/3=65. 65x3=195.
135. Every increase of 30 is also. Such as 165, 195, 225.
585 is divisible by these numbers: 1 3 5 9 13 15 39 45 65 117 195 and 585.
well, 1+9=10+5=15, which is divisible by 3, so it should be according to 3's divisabilaty rule.
Add the digits in 585 i.e. 5+8+5=18 18 is divisible by 3 Therefore, 585 is divisible by 3